Question
Download Solution PDFApproximately, the coefficient of variation for the given data where Pearson's second measure of skewness = 0.42, arithmetic mean = 86 and median = 80, is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
Pearsaons measure of skewness = 0.42
Mean = x̅ = 86
Median = Md = 80
Formula
Skewness = Skp = 3(Mean – median)/standard deviation
Calculation
0.42 = 3(x̅ - Md)/σ
⇒ 0.42 = 3(86 – 80)/σ
⇒ σ = 18/0.42
⇒ σ = 300/7
Coefficient of variation = standard deviation/mean = (σ/x̅) × 100
⇒ CV = (300/7/86) × 100
⇒ (300/7 × 86) × 100
∴ Coefficient of variation is 50
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