Question
Download Solution PDFAn OPAMP has a common mode gain of 0.01 and a differential mode gain of 105. Its common mode rejection ratio would be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Common mode rejection ratio(CMRR): It is the “ratio of the differential voltage gain (Ad) to the common-mode voltage gain (Acm)”.
The higher the value of CMRR the better is the matching between two input terminals and smaller is the output common-mode voltage.
CMRR = \( \frac{{{A_d}}}{{{A_{cm}}}}\)
It is infinity ∞ for the ideal op-amp.
Calculation:
Given that, common-mode gain = 0.01
Differential mode gain = 105
CMRR=\(\frac{{{{10}^5}}}{{0.01}}\) = 107.
Last updated on Jul 2, 2025
-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10.
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.