A uniform electric field in the plane of the paper as shown. Here A, B, C, D are the points on the circle V₁, V₂, V₃, V₄ are the potential at those points respectively. Then

CONCEPT:

• Electric lines of forces constitute the electric field and vice versa.
• Electric lines of force:  Inside the electric field, The path along which a unit positive charge will move if it is free to do so is called electric lines of force.
  • The tangent at any point to these lines gives the direction of the electric field at that point.
• E lectric lines of force always flow from higher potential to lower potential.

EXPLANATION:

• Electric lines of forces constitute the electric field and vice versa.
• Electric lines of force always flow from higher potential to lower potential.
• So in the given figure in the question, if we move from the left side to the right side, the potential will decrease.

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so V_C > V_A = V_B > V_D

• Since line joining A and B points is perpendicular to electric lines of force so both points will be at the same potential.
• From the above observation; \({V_C} > {V_A},\;{V_B} > {V_D}\) is correct. So the correct answer is option 3.