Question
Download Solution PDFA person has some coins of Rs. 10, Rs. 5, and Rs. 2 denominations. The ratio of the products of the numbers of Rs. 10 and Rs. 5 coins, the numbers of Rs. 5 and Rs. 2 coins, and the numbers of Rs. 2 and Rs. 10 coins is 3 ∶ 4 ∶ 2 respectively. What could be the minimum amount of money this person has?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The products of the numbers of Rs. 10 and Rs. 5 coins, the numbers of Rs. 5 and Rs. 2 coins, and the numbers of Rs. 2 and Rs. 10 coins is 3 ∶ 4 ∶ 2
Calculation:
Ratio = 3 : 4 : 2
By multiplying with 6 we get,
18 : 24 : 12
We write 18 : 24 : 12 as (6 × 3) : (6 × 4) : (4 × 3)
So, from this we can assume the number of 10 rupee coins are 3, number of 5 rupee coins are 6 and number of 2 rupee coins are 4
So, minimum possible amount could be 10 × 3 + 5 × 6 + 2 × 4
⇒ 30 + 30 + 8
⇒ 68
∴ The required answer is 68.
Last updated on May 28, 2025
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