Question
Download Solution PDFA heater of resistance 300Ω is connected to the main supply for 10 minutes. If the heat produced in the heater during this time is 18 J, then find the current through it.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The heat produced by the heater is given by:
\(H=i^2Rt\)
where, i = Current
R = Resistance
t = Time
Calculation
Given, R = 300 Ω
t = 10 min = 600 sec
H = 18 J
\(18=i^2(300)(600)\)
i = 0.01 A
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