Second Order Derivatives MCQ Quiz - Objective Question with Answer for Second Order Derivatives - Download Free PDF

Last updated on Jul 8, 2025

Latest Second Order Derivatives MCQ Objective Questions

Second Order Derivatives Question 1:

Let y(x) = (1 + x) (1 + x2) (1 + x4) (1 + x8) (1 + x16).

Then y' - y" at x = -1 is equal to

  1. 976 
  2. 464 
  3. 496 
  4. 944

Answer (Detailed Solution Below)

Option 3 : 496 

Second Order Derivatives Question 1 Detailed Solution

Calculation:

⇒ 

⇒ y' - xy' - y = -32x31

⇒ y" - xy" - y' - y' = -(32)(31)x30

at x = – 1 ⇒ y' - y" = 496

Hence, the correct answer is Option 3. 

Second Order Derivatives Question 2:

  1. -1
  2. 28
  3. 27
  4. 1

Answer (Detailed Solution Below)

Option 1 : -1

Second Order Derivatives Question 2 Detailed Solution

Calculation: 

Applying C3 → C3 -C1

Hence, the correct answer is Option 1.

Second Order Derivatives Question 3:

Find 

  1. None of the above

Answer (Detailed Solution Below)

Option 2 :

Second Order Derivatives Question 3 Detailed Solution

Concept:

Suppose that we have two functions f(x) and g(x) and they are both differentiable.

  • Chain Rule: 
  • Product Rule: 

 

Formulas:

 

Calculation:

Second Order Derivatives Question 4:

If y = 100e2x - 200e-2x and  = ay then a = ________.

  1. 4
  2. -4
  3. 2
  4. 0

Answer (Detailed Solution Below)

Option 1 : 4

Second Order Derivatives Question 4 Detailed Solution

Calculation:

 y = 100e2x - 200e-2x

Differentiate y with respect to x:

Differentiate again with respect to x:

Factor out 4:

Comparing with , we get a = 4.

Hence option 1 is correct

Second Order Derivatives Question 5:

If  then 

Answer (Detailed Solution Below)

Option 1 :

Second Order Derivatives Question 5 Detailed Solution

Formula Used:

Chain rule for differentiation

Calculation:

Given:

Differentiating both sides w.r.t. x, we get

Differentiating again w.r.t. x, we get

Now, substituting the values of y and y'' in the expression , we get

Hence option 1 is correct

Top Second Order Derivatives MCQ Objective Questions

Answer (Detailed Solution Below)

Option 4 :

Second Order Derivatives Question 6 Detailed Solution

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Concept:

Suppose that we have two functions f(x) and g(x) and they are both differentiable.

  • Product Rule: 
  • Division rule: 

 

Formulas:

Calculation:

⇒ 

If y = p cos 2x + q sin 2x, then  is equal to?

  1. -2y
  2. -4y
  3. 2y
  4. 4y

Answer (Detailed Solution Below)

Option 2 : -4y

Second Order Derivatives Question 7 Detailed Solution

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Concept:

 

Calculation:

Given: y = p cos 2x + q sin 2x                    .... (1)

Differentiating with respect to x, we get

As we know that, 

Again, differentiating with respect to x, we get

From equation (1), we get

If x =  and y = , then find the value of .

  1. 0

Answer (Detailed Solution Below)

Option 4 : 0

Second Order Derivatives Question 8 Detailed Solution

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Concept:

Chain Rule of Derivatives:

  • .
  • .


Product Rule of Derivatives:

  • .


Calculation:

We have x =  and y = .

We observe that x + y =  = 1.

Differentiating w.r.t. x, we get:

1 +  = 0

⇒  = -1

Differentiating again w.r.t. x, we get:

.

Find x2y2 + xy1, if y = sin (log x) ?

  1. y
  2. -y
  3. xy
  4. -xy

Answer (Detailed Solution Below)

Option 2 : -y

Second Order Derivatives Question 9 Detailed Solution

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CONCEPT:

0\)

CALCULATION:

Given: y = sin (log x)

First let's find out y1

As we know that,  and  0\)

⇒ 

Now, again by differentiating the above equation with respect to x we get,

As we know that, 

⇒ 

Now, x2y2 + xy1 = -y

Hence, correct option is 2.

Find 

  1. 370x187 
  2. 360x18 
  3. 380x18 
  4. 340x18 

Answer (Detailed Solution Below)

Option 3 : 380x18 

Second Order Derivatives Question 10 Detailed Solution

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Concept:

 

Calculation:

To Find: 

= 20 × 19 × x18

= 380x18 

Answer (Detailed Solution Below)

Option 1 :

Second Order Derivatives Question 11 Detailed Solution

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Concept:

Suppose that we have two functions f(x) and g(x) and they are both differentiable.

  • Chain Rule: 
  • Product Rule: 


Formulas:



Calculation:

What is the second derivative of tan 2x?

  1. 8 tan2 2x sec2 2x
  2. 8 tan 2x sec 2x
  3. 8 tan 2x sec2 2x
  4. None of these.

Answer (Detailed Solution Below)

Option 3 : 8 tan 2x sec2 2x

Second Order Derivatives Question 12 Detailed Solution

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Concept:

Chain Rule of Derivatives:

  • .
  • .

 

Derivatives of Trigonometric Functions:

 

Calculation:

Using the chain rule of derivatives, we get:

 = 2 sec2 2x

Again differentiation in respect to x, we get

=2 (2 sec 2x)(tan 2x sec 2x)(2)

= 8 tan 2x sec2 2x

Find 

  1. sec2 x
  2. 2sec2 x tan x
  3. sec x tan x
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 2sec2 x tan x

Second Order Derivatives Question 13 Detailed Solution

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Concept:

 

Suppose that we have two functions f(x) and g(x) and they are both differentiable.

  • Chain Rule: 
  • Product Rule: 


Formulas:



Calculation:

We have to find the value of 

Apply chain rule, we get

= 2sec x . sec x tan x

= 2sec2 x tan x

Find 

  1. 10(x9)
  2. 90(x8)
  3. 90(x9)
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 90(x8)

Second Order Derivatives Question 14 Detailed Solution

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Concept:



Calculation:

To Find: 

= 10 × 9 × x8

= 90(x8)

If y = 5 cos x - 3 sin x then 

  1. y
  2. 2y
  3. y/2
  4. -y

Answer (Detailed Solution Below)

Option 4 : -y

Second Order Derivatives Question 15 Detailed Solution

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CONCEPT:

CALCULATION:

Given: y = 5 cos x - 3 sin x

First let's find out dy/dx

As we know that,  and 

⇒ dy/dx = - 5 sin x - 3 cos x

Now, again by differentiating the above equation with respect to x we get,

Hence, correct option is 4.

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