Quick Math MCQ Quiz - Objective Question with Answer for Quick Math - Download Free PDF

Given:

Journey Started = 16 : 45

Journey Finished = 23 : 10

Concept:

1 hour = 60 minutes

Journey Completion Time = Journey Finished - Journey Started

Calculation:

Journey Completion Time = Journey Finished - Journey Started

= 23 : 10 - 16 : 45 = (22 + 1 hour) ∶ 10 - 16 : 45

⇒ 22 ∶ (60 + 10) - 16 : 45

⇒ 22 ∶ 70 - 16 : 45

⇒ 6 hours 25 minutes

Given:

Total number of candidates = 100

Number of candidates who likes vanilla = 50

Number of candidates who like Chocolate = 28

Number of candidates who likes Strawberry = 43

Number of candidates who like all three flavors = 5

Number of candidates who likes vanilla and chocolate = 13

Number of candidates who likes chocolate and strawberry = 11

Number of candidates who likes strawberry and vanilla = 12

Calculation:

Number of candidates who like Chocolate and Strawberry but not vanilla =

= Candidates who like Chocolate and Strawberry - Candidates who like all three flavors

= 11 - 5

= 6

∴ Number of candidates who like Chocolate and Strawberry but not Vanilla = 6

Given:

In a 900 m race:

'A' beats 'B' by 270 m

'A' beats 'C' by 340 m

Formula used:

If 'A' beats 'B' by x meters and 'A' beats 'C' by y meters, then 'B' beats 'C' by:

Distance = y - x

Calculation:

'A' beats 'B' by 270 m

'A' beats 'C' by 340 m

⇒ Distance by which 'B' beats 'C' = 340 - 270

⇒ Distance = 70 m

∴ The correct answer is option (2).

Given:

The sum of two consecutive even numbers is to be calculated where the difference of their squares is 84.

Formula Used:

Difference of squares = (a + b)(a - b)

Sum of two consecutive even numbers = a + b

Calculation:

Let the two consecutive even numbers be a and b.

Since they are consecutive even numbers, a = b - 2.

Difference of squares = 84

(b² - a²) = 84

⇒ (b + a)(b - a) = 84

Substitute a = b - 2:

⇒ (b + (b - 2))(b - (b - 2)) = 84

⇒ (b + b - 2)(2) = 84

⇒ (2b - 2)(2) = 84

⇒ 4b - 4 = 84

⇒ 4b = 88

⇒ b = 22

Substitute b = 22 to find a:

a = b - 2

a = 22 - 2

a = 20

Sum of a and b:

⇒ a + b = 20 + 22 = 42

The sum of two consecutive even numbers is 42.

Given:

Total number of students = 500

Students who can speak Hindi = 475

Students who can speak English = 200

We need to find the number of students who can speak Hindi only.

Formula Used:

Number of students who can speak Hindi only = Total students who can speak Hindi - Students who can speak both Hindi and English

Number of students who can speak both Hindi and English = (Students who can speak Hindi + Students who can speak English) - Total students

Calculation:

Number of students who can speak both Hindi and English = (475 + 200) - 500

⇒ Number of students who can speak both Hindi and English = 675 - 500

⇒ Number of students who can speak both Hindi and English = 175

Number of students who can speak Hindi only = 475 - 175

⇒ Number of students who can speak Hindi only = 300

The number of students who can speak Hindi only is 300.

Given:

10 × 20 × 30 × ... × 1000

Concept used:

Take 10 as common from each term.

Number of trailing zeroes in n! = Divide n by 5, continue this process until we get the value which is less than 5. Now, all quotients will be added and the resultant number will be the number of zeroes.

Calculations:

10 × 20 × 30 × ... × 1000

⇒ (10 × 1) × (10 × 2) × (10 × 3) × (10 × 4) ..........× (10 × 100)

⇒ 10¹⁰⁰ × (1 × 2 × 3 × ... × 100)

⇒ 10¹⁰⁰ × (100!)

Number of zeroes = 100 + {(100)/5 + (20)/5}

⇒ 100 + 20 + 4

⇒ 124

∴ The number of trailing zeroes in 10 × 20 × 30 × ... × 1000 is 124.

Given:

A mango kept in a basket doubles every one minute. 

The basket gets filled in 30 minutes. 

Calculation:

The basket is full (1) in 30 minutes. 

The Time required to fill the basket with mango is 30 minutes.

So, half the basket is filled in 29 minutes.

As in every minute, the basket gets doubled. So, in 29 minutes, it is half-filled and in the next minutes, it will be completely filled.

∴ Obviously, the basket will be half-filled (1/2) filled in 29 minutes. 

Alternate MethodAccording to the question,

1st min = 2¹ = 2

2nd min = 2² = 4

We have observed every min double the quantity

then in 29 min = 2²⁹ = 536870912

Last 30 min = 2³⁰ = 1073741824

We have observed the 29th min is half of the 30th min quantity.

According to the question, let the following Venn diagram,

Now, 

e = 5%

b + e = 14%

⇒ b = 9%

and,

d + e = 18%

⇒ d = 13%

Therefore, 

Percentage of students who failed only in Economics = a = 41% - (b + e + d)

a = 41% - (9 + 5 + 13)%

a = 41% - 27%

a = 14%

Hence, 14% is the correct answer.

Given:

20% of the boys and 15% of the girls failed the exam.

Total number of students who failed = 90

Calculation:

The percentage of boys who passed = (100 - 20)% = 80%

The percentage of girls who passed = (100 - 15)% = 85%

Let, the number of appeared boys = x

The number of appeared girls = y

So, 80x/100 - 85y/100 = 70

⇒ 5 (16x - 17y) = 7000

⇒ 16x - 17y = 1400   .....(1)

Also, 20x/100 + 15y/100 = 90

⇒ 5 (4x + 3y) = 9000

⇒ 4x + 3y = 1800   .....(2)

Multiplying 4 to equation (2),

16x + 12y = 7200   .....(3)

Subtracting equation (2) from equation (3),

16x + 12y - 16x + 17y = 7200 - 1400

⇒ 29y = 5800

⇒ y = 5800/29 = 200

∴ The number of girls appeared = 200

Putting y = 200 in equation (2),

4x + 3 × 200 = 1800

⇒ 4x = 1800 - 600 = 1200

⇒ x = 1200/4 = 300

∴ The number of boys who appeared = 300

The total number of students who appeared = 300 + 200 = 500

∴ The number of students that appeared for the exam is 500

Alternate Method Calculation:-

Let the Number of boys and Girls who appeared in exam be x and y respectively,

So, according to question-

Number of boys passed in exam = [(100 - 20) × x]/100 = 0.80x

Number of girls passed in exam = [(100 - 15) × y]/100 = 0.85y

Condition (1) -  

⇒ 0.80x = 0.85y + 70

⇒ 0.80x - 0.85y = 70    ...(i)

Condition (2) -

Total failed students = 90

⇒ 0.20x + 0.15y = 90    ...(ii)

From eqⁿ (1) - [4 × eqⁿ (ii)]

⇒ (-0.85y) - 0.60y = 70 - 360 

⇒ 1.45y = 290

⇒ y = 200

Put this value in eqⁿ (i)

⇒ 0.80x = 0.85 × 200 + 70

⇒ 0.80x = 170 + 70 = 240

⇒ x = 300

So, total number of students appeared in exam = 300 + 200 = 500.

Given:

Let the number be x.

Correct value = x/2

Resultant number = 2 × x

Calculations:

According to Question,

Required percentage = Resultant number/Correct value × 100

⇒ Required percentage = [(2x)/(x/2)] × 100

⇒ Required percentage = 400%

Concept:

To find the square root of any number, factorize it.

Calculation:

4050 = 2 × 3 × 3 × 3 × 3 × 5 × 5

If we multiply by 2 in 4050

⇒ 4050 × 2 = 8100

Now, √8100 = √(2 × 2 × 3 × 3 × 3 × 3 × 5 × 5)

⇒ √8100 = 2 × 3 × 3 × 5 = 90

∴ Multiply 4050 by 2 to get 8100 of which square root is 90.

Given:

Sum of three consecutive multiples of 5 is 285

Calculation:

Three consecutive numbers are x, x + 1 and x + 2

So, Three consecutive multiples of 5 are 5x, 5(x + 1) and 5(x + 2)

The sum of three consecutive multiple of 5 is 285

∴ 5x + 5x + 5 + 5x + 10 = 285

⇒ 15x = 270

⇒ x = 18

Now, largest number = 5(x + 2) = 5 × 20 = 100

Concept used:

Factorize the given number and then make pairs of same numbers to get the possible square factors

Calculation:

⇒ 21600 = 2² × 2² × 2 × 3² × 3 × 5²

Factors of 21600 that are perfect squares is

⇒ 1

⇒ 2² = 4,

⇒ 3² = 9,

⇒ 2² × 2² = 16

⇒ 5² = 25

⇒ 2² × 3² = 36

⇒ 2² × 5² = 100

⇒ 2² × 2² × 3² = 144

⇒ 3² × 5² = 225

⇒ 2² × 2² × 5² = 400

⇒ 3² × 5² × 2² = 900

⇒ 32 × 52 × 2⁴ = 3600

Number of factors of 21600 whose perfect square = 12

∴  Factors of the number 21600 perfect squares is 12

Given:

Total number of students = 100

Students passed in Mathematics = 50

Students passed in English = 70

Students failed in both subjects = 5

Concept used:

The number of students who passed in both subjects is found by finding the difference between the number of students required for no overlap and the given total.

Calculation:

Students who passed in both the subjects = 70 + 50 – (100 – 5)

⇒ 120 – 95 = 25

∴ The students who passed in both subjects is 25.

Alternate Method

Total number of students = 100

Number of students failed in both subject = 5

⇒ Number of students passed in any one or both subject = (100 - 5) = 95

Students passed in Mathematics = 50

⇒ Students failed in Mathematics but passed in English = (95 - 50) = 45

Students passed in English = 70

⇒ Students failed in English but passed in Mathematics = (95 - 70) = 25

Number of students passed in both subjects = (95 - 45 - 25) = 25

∴ The number of students who passed in both subjects is 25.

Given:

A college hostel mess has provisions for 25 days for 350 boys.

At the end of 10 days, when some boys were shifted to another hostel, it was found that now the provisions will last for 21 more days.

Concept used:

Available provisions = Number of days × Number of boys

Calculation:

Available provisions = 25 × 350 = 8750 units

After 10 days the remaining provision = 8750 - 10 × 350

⇒ 5250 units

Let N number of boys shifted to another hostel.

According to the question,

(350 - N) × 21 = 5250

⇒ 350 - N = 5250/21

⇒ 350 - N = 250

⇒ N = 350 - 250

⇒ N = 100

∴ 100 boys were shifted to another hostel.