Phase Equilibrium MCQ Quiz - Objective Question with Answer for Phase Equilibrium - Download Free PDF

Last updated on Jul 15, 2025

Latest Phase Equilibrium MCQ Objective Questions

Phase Equilibrium Question 1:

The phase diagram of a single component system is given below. 

The option with the correct number of degrees of freedom corresponding to the labelled points i, j, and k, respectively, is

  1. 0, 1, 2 
  2. 3, 2, 1 
  3. 2, 0, 1 
  4. 0, 2, 1 

Answer (Detailed Solution Below)

Option 1 : 0, 1, 2 

Phase Equilibrium Question 1 Detailed Solution

CONCEPT:

Degrees of Freedom in Phase Diagrams

F = C - P + 2

  • The degrees of freedom (F) of a system can be calculated using the Gibbs phase rule:
    • C is the number of components in the system (in this case, a single component system, so C = 1),
    • P is the number of phases in equilibrium at the point in the phase diagram.
  • At different points in a phase diagram, the number of phases (P) can vary, affecting the degrees of freedom.

EXPLANATION:

  • For example:
    • At point j, three phases meet (P = 3), so the system has zero degrees of freedom (F = 0).
    • At point i, two phases meet (P = 2), so the system has one degree of freedom (F = 1).
    • At point k, the system is in a single phase (P = 1), so the system has two degrees of freedom (F = 2).
  • At point i (boundary between two phases), there is 1 degree of freedom because temperature and pressure can be varied independently.
  • At point j (triple point where three phases meet), there are zero degrees of freedom because all variables (temperature and pressure) are fixed by the equilibrium of the three phases.
  • At point k (single phase region), there are 2 degrees of freedom because both temperature and pressure can be varied independently.

Therefore, the degrees of freedom corresponding to points i, j, and k are 0, 1, and 2, respectively.

Phase Equilibrium Question 2:

The expressions for the vapour pressure of solid (𝑝1) and vapour pressure of liquid (𝑝2) phases of a pure substance, respectively, are 

The triple point temperature of this substance is ____ K (in integer).

Answer (Detailed Solution Below) 400

Phase Equilibrium Question 2 Detailed Solution

CONCEPT:

Triple Point Temperature and Vapor Pressure Equality

ln(p1) = ln(p2)

  • The triple point of a substance is the unique temperature and pressure at which all three phases (solid, liquid, and gas) coexist in equilibrium.
  • At the triple point, the vapor pressure of the solid phase (p1) is equal to that of the liquid phase (p2):
  • Given expressions:
    • ln(p1) = -2000/T + 5
    • ln(p2) = -4000/T + 10

EXPLANATION:

  • At the triple point:

    ln(p1) = ln(p2)
    ⇒ -2000/T + 5 = -4000/T + 10

  • Rearranging terms:

    -2000/T + 4000/T = 10 - 5
    ⇒ 2000/T = 5

  • Solving for T:

    T = 2000 / 5 = 400 K

Therefore, the triple point temperature of the substance is 400 K.

Phase Equilibrium Question 3:

The variation of molar heat capacity at constant volume (CV, m) with temperature (T) of a gaseous diatomic molecule is shown in the diagram below. The values of X, Y and Z, respectively, are

The diagram is not to the scale and discontinuity in the diagram represents dissociation] 

  1. 2.0 R, 2.5 R, 3.0 R 
  2. 2.5 R, 3.0 R, 3.5 R 
  3. 3.5 R, 4.0 R, 4.5 R 
  4. 3.0 R, 3.5 R, 4.0 R 

Answer (Detailed Solution Below)

Option 2 : 2.5 R, 3.0 R, 3.5 R 

Phase Equilibrium Question 3 Detailed Solution

CONCEPT:

Variation of Molar Heat Capacity (CV,m) with Temperature for a Diatomic Gas

  • Diatomic molecules exhibit contributions to heat capacity from different degrees of freedom as temperature increases:
    1. Translational motion: Always active → contributes (3/2)R
    2. Rotational motion: Becomes active at moderate temperatures → adds R ⇒ Total = 2.5 R
    3. Vibrational motion: Activates at higher temperatures → adds another R (from both potential and kinetic energy) ⇒ Total = 3.5 R
  • The sharp jump (discontinuity) in the graph represents dissociation, beyond which CV can decrease due to bond breakage and energy redistribution.

EXPLANATION:

  • At low T → only translational and rotational DOF contribute ⇒ X = 2.5 R
  • At moderate T → vibrational modes begin to contribute ⇒ Y = 3.0 R
  • At high T before dissociation is complete → full vibrational contribution ⇒ Z = 3.5 R

Therefore, the correct sequence is: X = 2.5 R, Y = 3.0 R, Z = 3.5 R — Option 2.

Phase Equilibrium Question 4:

The decomposition of CaCO3 in a closed vessel is represented by the equation

CaCO3(s)  CaO(s) + CO2(g)

Calculate the number of phases. components and degree of freedom

  1. p = 2: C = 3; F = 3
  2. p = 3: C = 2; F = 1
  3. p = 2: C = 2; F = 2
  4. p = 3: C = 3; F = 2

Answer (Detailed Solution Below)

Option 2 : p = 3: C = 2; F = 1

Phase Equilibrium Question 4 Detailed Solution

Concept:

Phase Rule and Calculation of Phases, Components, and Degrees of Freedom

  • The phase rule (Gibbs' phase rule) is a fundamental principle in thermodynamics that describes the relationship between the number of phases, components, and degrees of freedom in a system at equilibrium.
  • The phase rule is given by the equation:

    F = C - P + 2

    where:
    • F is the degrees of freedom (the number of independent variables, such as temperature and pressure, that can be changed independently).
    • C is the number of components (chemically independent substances in the system).
    • P is the number of phases (distinct forms of matter present, such as solid, liquid, and gas).

Explanation:

  • The decomposition of calcium carbonate (CaCO3) is represented by the reaction:

    CaCO3(s) ⇌ CaO(s) + CO2(g)

  • For this reaction:
    • Number of phases (P): The system contains three phases—solid CaCO3, solid CaO, and gaseous CO2. Therefore, p = 3.
    • Number of components (C): The components are CaCO3, CaO, and CO2. Thus, C = 2, because CaCO3 decomposes into CaO and CO2, making it two chemically independent components.
    • Degrees of freedom (F): Using the phase rule equation:

      F = C - P + 2

      F = 2 - 3 + 2 = 1

Hence, the correct answer is P = 3; C = 2; F = 1.

Phase Equilibrium Question 5:

The number of phases in a system when calcium carbonate undergoes thermal decomposition 

  1. 0
  2. 1
  3. 2
  4. 3

Answer (Detailed Solution Below)

Option 4 : 3

Phase Equilibrium Question 5 Detailed Solution

Concept:

Phases in a System during Thermal Decomposition

The reaction is:

CaCO₃(s) → CaO(s) + CO₂(g)

  • The number of phases in a system refers to the distinct states of matter (solid, liquid, gas) present in the system during a chemical process.
  • When calcium carbonate undergoes thermal decomposition, it breaks down into calcium oxide and carbon dioxide gas.
  • In this reaction, calcium carbonate (CaCO₃) is solid, calcium oxide (CaO) is also solid, and carbon dioxide (CO₂) is a gas. Therefore, the system contains three distinct phases: solid, solid, and gas.

Explanation:

  • The decomposition of calcium carbonate involves solid calcium carbonate (CaCO₃) turning into solid calcium oxide (CaO) and gaseous carbon dioxide (CO₂).
  • Thus, there are three phases in the system: solid (CaCO₃), solid (CaO), and gas (CO₂).

Therefore, the correct answer is: 3 phases.

Top Phase Equilibrium MCQ Objective Questions

Phase Equilibrium Question 6:

The decomposition of CaCO3 in a closed vessel is represented by the equation

CaCO3(s)  CaO(s) + CO2(g)

Calculate the number of phases. components and degree of freedom

  1. p = 2: C = 3; F = 3
  2. p = 3: C = 2; F = 1
  3. p = 2: C = 2; F = 2
  4. p = 3: C = 3; F = 2

Answer (Detailed Solution Below)

Option 2 : p = 3: C = 2; F = 1

Phase Equilibrium Question 6 Detailed Solution

Concept:

Phase Rule and Calculation of Phases, Components, and Degrees of Freedom

  • The phase rule (Gibbs' phase rule) is a fundamental principle in thermodynamics that describes the relationship between the number of phases, components, and degrees of freedom in a system at equilibrium.
  • The phase rule is given by the equation:

    F = C - P + 2

    where:
    • F is the degrees of freedom (the number of independent variables, such as temperature and pressure, that can be changed independently).
    • C is the number of components (chemically independent substances in the system).
    • P is the number of phases (distinct forms of matter present, such as solid, liquid, and gas).

Explanation:

  • The decomposition of calcium carbonate (CaCO3) is represented by the reaction:

    CaCO3(s) ⇌ CaO(s) + CO2(g)

  • For this reaction:
    • Number of phases (P): The system contains three phases—solid CaCO3, solid CaO, and gaseous CO2. Therefore, p = 3.
    • Number of components (C): The components are CaCO3, CaO, and CO2. Thus, C = 2, because CaCO3 decomposes into CaO and CO2, making it two chemically independent components.
    • Degrees of freedom (F): Using the phase rule equation:

      F = C - P + 2

      F = 2 - 3 + 2 = 1

Hence, the correct answer is P = 3; C = 2; F = 1.

Phase Equilibrium Question 7:

The variation of molar heat capacity at constant volume (CV, m) with temperature (T) of a gaseous diatomic molecule is shown in the diagram below. The values of X, Y and Z, respectively, are

The diagram is not to the scale and discontinuity in the diagram represents dissociation] 

  1. 2.0 R, 2.5 R, 3.0 R 
  2. 2.5 R, 3.0 R, 3.5 R 
  3. 3.5 R, 4.0 R, 4.5 R 
  4. 3.0 R, 3.5 R, 4.0 R 

Answer (Detailed Solution Below)

Option 2 : 2.5 R, 3.0 R, 3.5 R 

Phase Equilibrium Question 7 Detailed Solution

CONCEPT:

Variation of Molar Heat Capacity (CV,m) with Temperature for a Diatomic Gas

  • Diatomic molecules exhibit contributions to heat capacity from different degrees of freedom as temperature increases:
    1. Translational motion: Always active → contributes (3/2)R
    2. Rotational motion: Becomes active at moderate temperatures → adds R ⇒ Total = 2.5 R
    3. Vibrational motion: Activates at higher temperatures → adds another R (from both potential and kinetic energy) ⇒ Total = 3.5 R
  • The sharp jump (discontinuity) in the graph represents dissociation, beyond which CV can decrease due to bond breakage and energy redistribution.

EXPLANATION:

  • At low T → only translational and rotational DOF contribute ⇒ X = 2.5 R
  • At moderate T → vibrational modes begin to contribute ⇒ Y = 3.0 R
  • At high T before dissociation is complete → full vibrational contribution ⇒ Z = 3.5 R

Therefore, the correct sequence is: X = 2.5 R, Y = 3.0 R, Z = 3.5 R — Option 2.

Phase Equilibrium Question 8:

The number of phases in a system when calcium carbonate undergoes thermal decomposition 

  1. 0
  2. 1
  3. 2
  4. 3

Answer (Detailed Solution Below)

Option 4 : 3

Phase Equilibrium Question 8 Detailed Solution

Concept:

Phases in a System during Thermal Decomposition

The reaction is:

CaCO₃(s) → CaO(s) + CO₂(g)

  • The number of phases in a system refers to the distinct states of matter (solid, liquid, gas) present in the system during a chemical process.
  • When calcium carbonate undergoes thermal decomposition, it breaks down into calcium oxide and carbon dioxide gas.
  • In this reaction, calcium carbonate (CaCO₃) is solid, calcium oxide (CaO) is also solid, and carbon dioxide (CO₂) is a gas. Therefore, the system contains three distinct phases: solid, solid, and gas.

Explanation:

  • The decomposition of calcium carbonate involves solid calcium carbonate (CaCO₃) turning into solid calcium oxide (CaO) and gaseous carbon dioxide (CO₂).
  • Thus, there are three phases in the system: solid (CaCO₃), solid (CaO), and gas (CO₂).

Therefore, the correct answer is: 3 phases.

Phase Equilibrium Question 9:

The triangular coordinates for three - component system is given as 

The mole fractions of xA, xB and xC for point e are : 

  1. 0.10, 0.20, 0.30
  2. 0.20, 0.40, 0.40
  3. 0.20, 0.75, 0.05
  4. 0.25, 0.25, 0.50

Answer (Detailed Solution Below)

Option 2 : 0.20, 0.40, 0.40

Phase Equilibrium Question 9 Detailed Solution

Concept:

Triangular Diagram for a Three-Component System

  • A triangular diagram is used to represent the composition of a three-component system (A, B, and C) in terms of mole fractions.
  • Each vertex of the triangle represents 100% of one component (xA, xB, or xC), while the opposite side corresponds to 0% of that component.
  • The sum of the mole fractions of all three components at any point inside the triangle is always equal to 1:

    xA + xB + xC = 1

Explanation:

  • For point e on the diagram:
    • The value of xA is determined by measuring the perpendicular distance from point e to the side opposite to vertex A. This value is approximately 0.20.
    • The value of xB is determined by the perpendicular distance from point e to the side opposite to vertex B. This value is approximately 0.40.
    • The value of xC is determined by the perpendicular distance from point e to the side opposite to vertex C. This value is also approximately 0.40.
  • Hence, the mole fractions of xA, xB, and xC for point e are 0.20, 0.40, and 0.40, respectively.

Therefore, the correct answer is: 0.20, 0.40, 0.40.

Phase Equilibrium Question 10:

The number of degrees of freedom for liquid water and water vapour in equilibrium at a pressure of 1 atm is

  1. 0
  2. 1
  3. 2
  4. 3

Answer (Detailed Solution Below)

Option 1 : 0

Phase Equilibrium Question 10 Detailed Solution

Concept:

Degrees of Freedom and Reduced Phase Rule

  • The degrees of freedom (F) in a system are determined using Reduced Gibbs' Phase Rule:

    F = C - P + 1

    where:
    • F = degrees of freedom
    • C = number of components
    • P = number of phases in equilibrium
  • This applies when considering a condensed system, where the pressure is essentially constant and the only relevant variables are temperature and composition, effectively reducing the number of degrees of freedom by one. 

Explanation:

  • System: Liquid water and water vapor are in equilibrium at 1 atm pressure.
  • Number of components (C): The system has one component, H2O.
  • Number of phases (P): Two phases are present: liquid and vapor.
  • Calculation:

    F = C - P + 1

    F = 1 - 2 + 1

    F = 0

Therefore, the number of degrees of freedom is: 0.

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